A sample of hydrogen gas is found to occupy 906 cm of
volume at 300 K. Calculate the temperature at which it will
occupy 500 cm of volume? (Assuming amount and pressure
remains constant.)
Answers
Answered by
0
Answer:
Given informations are stated below :
V1 = 906 cm³
T1 = 300 K
V2 = 500 cm³
T2 = ?
Mentioned, pressure remains constant.
So, BY CHARLES' LAW, WE GET :
V1/T1 = V2/T2
=> 906/300 = 500/T2
=> 906 × T2 = 500 × 300
=> T2 = (500×300)/906
=> T2 = 165.56°C or 165.6°C (Approx.)
Explanation:
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Answered by
0
Answer:The answer is
324
m
L
.
This is a simple application of Boyle's law
P
1
V
1
=
P
2
V
2
,
which states that a gas' pressure and volume are proportional to eachother. It can be derived from the combined gas law,
P
V
=
n
R
T
, by keeping
T
constant.
So, we have
V
2
=
P
1
P
2
⋅
V
1
=
0.971
1.50
⋅
500
m
L
=
324
m
L
-> pressure increases, volume decreases and vice versa.
Explanation:
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