Question

A sample of hydrogen gas occupies 10L at 200 mm pressure. What would be the volume of this
sample at 1 atm. pressure, if temperature is kept constant ?

Answer 1

Answer:

volume 1 = 10 L

pressure 1 = 200 mm

volume 2 = v²

pressure 2 = 760 mm (1atm = 760mm)

let volume be v and pressure be p

Applying, Boyles law

p¹ v¹ = p² v²

putting the value in above formulae we get,

200 × 10 = 1 × v²

v² = (200×10)/760

v² = 2000/760

v² = 2.63157895

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Answer 2

According to Charle's Law : For a fixed mass of gas at constant pressure (P) ,the volume is directly proportional to the kelvin temperature (T).

V ∝ T

Or, T1 /T2 = V1 /V2

V1 = 400 cm3

T1 = 300 K

V2 = ?

T2 = 283 K

V2 = V1 / T1 x T2

= 400 cm3/ 300 K x 283 K

= 377 cm3