A sample of K2SO4.Al2(SO4)3.24H20 contains 5 kg oxygen then mass of sulphur (in kg) in
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Answered by
7
Answer:
Explanation:
1 mole of pure potash alum contains 40 atoms of oxygen
40 atoms of oxygen weigh=40*16=640 g=0.64kg
That means that 1 mole of pure potash alum is present
Weight of 1 mole of pure potash alum
=2*39+4*32+2*27+40*16+48*1
=948 g= 0.948 kg
Answered by
5
Answer:
1280gm
Explanation:
(Moles of substance*40)no.of Oxygen
40*x*16=6400gram
x=10moles
no. of moles of s =4*10
=40moles
weight of sulphur (after multiplying it by mass of given compound)
=1280gm
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❤️Hopefully it will help uh
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