Chemistry, asked by rk5551564p3mq5w, 1 year ago

A sample of KCLO3 on decomposition yielded 448 ml of oxygen gas at NTP. Calculate weight of oxygen product .

Answers

Answered by BarrettArcher
5

Answer : The weight of oxygen is, 0.5856 gram.

Solution :

Using ideal gas equation,

PV=nRT

where,

At NTP,

P = pressure of the gas  = 1 atm

V = volume of the gas  = 448 ml = 0.448 L    (1 L = 1000 ml)

T = temperature of the gas  = 298.15 K

n = number of moles of gas

R = Gas constant = 0.0821 Latm/moleK

Now put all the given values in the above formula, we get

n=\frac{PV}{RT}

n=\frac{(1atm)\times (0.448L)}{(0.0821Latm/moleK)\times (298.15K)}=0.0183moles

Now we have to calculate the mass of oxygen.

The molar mass of Oxygen = 32 g/mole

\text{Mass of oxygen}=\text{Moles of oxygen}\times \text{Molar mass of oxygen}

\text{Mass of oxygen}=0.0183moles\times 32g/mole=0.5856g

Therefore, the weight of oxygen is, 0.5856 gram.

Answered by abhishekroyrfj
2

Answer:

The answer is :0.64g

Explanation:

One mol of an ideal gas occupies 22.4L volume.

1 mol O2-32g

THUS,1 mol O2(or 32g O2) occupy 22.4L volume.

Also,22.4L volume occupied by 32g O2

Thus,0.448L volume occupied by

(32/22.4 multiplied by 0.448)=0.64g.

Thanks

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