A sample of KCLO3 on decomposition yielded 448 ml of oxygen gas at NTP. Calculate weight of oxygen product .
Answers
Answered by
5
Answer : The weight of oxygen is, 0.5856 gram.
Solution :
Using ideal gas equation,
where,
At NTP,
P = pressure of the gas = 1 atm
V = volume of the gas = 448 ml = 0.448 L (1 L = 1000 ml)
T = temperature of the gas = 298.15 K
n = number of moles of gas
R = Gas constant = 0.0821 Latm/moleK
Now put all the given values in the above formula, we get
Now we have to calculate the mass of oxygen.
The molar mass of Oxygen = 32 g/mole
Therefore, the weight of oxygen is, 0.5856 gram.
Answered by
2
Answer:
The answer is :0.64g
Explanation:
One mol of an ideal gas occupies 22.4L volume.
1 mol O2-32g
THUS,1 mol O2(or 32g O2) occupy 22.4L volume.
Also,22.4L volume occupied by 32g O2
Thus,0.448L volume occupied by
(32/22.4 multiplied by 0.448)=0.64g.
Thanks
Similar questions
Math,
8 months ago
Social Sciences,
8 months ago
Social Sciences,
8 months ago
Science,
1 year ago
Geography,
1 year ago
Chemistry,
1 year ago
English,
1 year ago