Question

A sample of koh weighing 0.28g is dissolved in water and the solution is made to 50.0ml in volumetric flask.What is the molarity of the resulting solution?

Answer 1

so molar mass of KOH=39+16+1=56 gram ,,

given mass= 0.28 gram.. so no. of moles= given mass/ molar mass

so 0.28/56=0.05 moles of KOH (are present in solution)

we KNOW KOH IS SOLUTE.

solution=50ml

in litres=50/1000=0.05 litres

molarity= no. of moles of solute/ volume of solution (in litres)

= 0.05moles of solute/0.05 litres of solution= 1M

0R WE CAN SAY MOLARITY= 1..

i hope you got the method and if not don't worry do more practice.. you can do this...

Answer 2

so molar mass of KOH=39+16+1=56 gram ,,

given mass= 0.28 gram.. so no. of moles= given mass/ molar mass

so 0.28/56=0.05 moles of KOH (are present in solution)

we KNOW KOH IS SOLUTE.

solution=50ml

in litres=50/1000=0.05 litres

molarity= no. of moles of solute/ volume of solution (in litres)

= 0.05moles of solute/0.05 litres of solution= 1M

0R WE CAN SAY MOLARITY= 1..

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