Question

A sample of lime stone contains 80% CaCO3. Calculate the volume of CO2 obtained at STP. when 25 g of this sample react with excess of dil HCl.

Answer 1

4.48 litres of CO₂ gas at STP.

Step - by - step Explanation: Okay, let 100g of limestone contain 80% of CaCO₃.

Amount of pure CaCO₃ = 80/100 × 100

→ 80 grams of pure CaCO₃

100 gram of impure CaCO₃ = 80 g pure

1 gram of impure CaCO₃ = 80/100 g pure

25 gram of impure CaCO₃ = 80/100 × 25

→ 20 grams of pure CaCO₃

CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O

(100 g/mol)

100 gram of CaCO₃ = 22.4 L of CO₂

1 gram of CaCO₃ = 22.4/100

20 gram of CaCO₃ = 22.4/100 × 20

→ 4.48 L of CO₂ gas

Answer 2

Answer:

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