Question

A sample of magnesium phosphate Mg3(Po4)2 contains 72 g magnesium in the sample . calculate the number of g molecules of oxygen in the sample​

Answer 1

Answer:

The number of gram molecules of Oxygen is 4 gram molecules of Oxygen

Explanation:

Mol wt of Mg3(PO4)2 = 263 g

Wt of Magnesium present = 72 g

Number of Magnesium present = 72/24 = 3

So we can say that 1 mole of Mg3(PO4)2 = 3 moles of magnesium

Then how many moles of Oxygen are present in 1 mole of Mg3(PO4)2 ?

1 mole contains of Mg3(PO4)2 = 8 moles of oxygen

the weight of 8 moles of Oxygen = 128g

1 gram molecule of Oxygen = 32 g

? gram molecule of Oxygen = 128 g

128/32 = 4 gram molecules of Oxygen

Answer 2

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