A sample of mixture of CaCl2, and NaCl weighing 2.22 gm was treated to precipitate all the Ca as CaCO3, which was then heated and quantitatively converted to 0.84 gm of CaO. Calculate mass fraction of CaCl2, in the mixture.
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Answer:
45%
Explanation:
CaCO
3
→CaO+CO
2
The molar masses of CaCO
3
and CaO
are 100 and 56 g/mol respectively.
100 g of CaCO
3
will give 56 g of CaO
0.959 g CaO corresponds to
56
0.959×100
=1.72 g of CaCO
3
The molar mass of CaCl
2
is 111 g/mol.
1.72 g of CaCO
3
corresponds to
100
1.72×111
=1.9 g of
CaCl
2
The percent of CaCl
2
in sample is
4.22
1.9×100
=45.00 %
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