a sample of moist air at a total pressure of 85kpa has a dry bulb temperature of 30 deg.c (saturation vapour pressure of water =4.24kpa). if the air sample has relative humidity of 65% the absolute humidity (in grams) of watervapour per kg of dry air is
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Please find the answer below:
Keeping in view that; a sample of moist air at a total pressure of 85 kpa has a dry bulb temperature of 30 deg.c (saturation vapour pressure of water =4.24kpa).
If the air sample has relative humidity of 65% the absolute humidity (in grams) of water vapour per kg of dry air is 20.5-21 grams.
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Explanation:
The relation between relative humidity, saturation vapour pressure and actual vapour pressure is
P_{w} = P_{w, s}\times \frac{RH}{100}P
w
=P
w,s
×
100
RH
Here, RH=65\%RH=65% ,P_{w, s} = 4.24 KPaP
w,s
=4.24KPa
Therefore,
P_{w} =4.24 KPa \times \frac{65}{100}P
w
P_{w}=2.76 KpaP
w
=2.76Kpa
Now the absolute humidity,
AH=622\times\frac{P_{w} }{P_{T} }
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