Question

A sample of N2O gas has a density of 2.85 g/L at 298 K. What must be the pressure of the gas (in mmHg)?

Answer 1

Hello Dear,

● Answer -

P = 1203 mm Hg

● Explanation -

# Given -

ρ = 2.85 g/L

T = 298 K

# Solution -

According to ideal gas equation -

PV = nRT

PV = (W/M)RT

PM = (W/V)RT

PM = ρRT

P = ρRT/M

P = 2.85 × 0.082 × 298 / 44

P = 1.583 atm

P = 1.583 × 760

P = 1203 mm Hg

Therefore, pressure of the gas must be 1203 mm of Hg.

Hope this helps you..