Question

a sample of nano3 weighing 0.38g is place din 250ml find the moplarity

Answer 1

Molar mass of NaNO3 = 23 + 14 + 16x3 = 85 g/mol


Number of moles of NaNO3 = 0.38/85 = 0.00447

Volume of solution = 250/1000 = 0.25 litres



Molarity = Number of moles/Volume in litres


Molarity = 0.00447/0.25

             = 0.018M

Answer 2

Answer:

Step-by-step explanation:

Molar mass of NaNO3 = 23 + 14 + 16x3 = 85 g/mol

Number of moles of NaNO3 = 0.38/85 = 0.00447

Volume of solution = 250/1000 = 0.25 litres

Molarity = Number of moles/Volume in litres

Molarity = 0.00447/0.25

= 0.018M