Chemistry, asked by shamshersingh7796, 8 months ago

A sample of NaOH weighing 0.38g is dissolved in water and the solution is made to 50.0 ml in a volumertric flask .what is the molerity of the resulting solution? ​

Answers

Answered by sangeethailaiyaraja1
1

Answer:

Answer. Answer: 0.19 mol/ L is the molarity of the resulting solution

Answered by Pallakavya
1

Explanation:

Answer:

0.19 mol/ L is the molarity of the resulting solution.

Explanation:

Mass of sodium = 0.38 g

Volume of the solution = 50 mL= 0.050 L

Molarity=\frac{\text{Mass of NaOH}}{\text{Molar mass of NaOH}\times \text{Volume of solution(L)}}Molarity=

Molar mass of NaOH×Volume of solution(L)

Mass of NaOH

M=\frac{0.38 g}{40 g/mol\times 0.050 L}=0.19 mol/lM=

40g/mol×0.050L

0.38g

=0.19mol/l

0.19 mol/ L is the molarity of the resulting solution.

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