Question

A sample of neon gas occupies 0.271 L at 84.5 kPa. What will be its volume at 25.4 kPa pressure?

Answer 1

Answer:

Boyle’s law states that

PV = constant when temperature is constant

4.2 L

Answer 2

Explanation:

V₁ = 0.271 L                   V₂ = ?

P₁ = 84.5 KPa                 P₂ = 25.4 KPa

Using the formula of Boyle's Law,

P₁ ˣ V₁ = P₂ ˣ V₂

V₂ = P₁ ˣ V₁/P₂

V₂ = 84.5 × 0.271/ 25.4

V₂ =22.8995/25.4

V₂ = 0.901555 L

V₂ ≈ 0.902 L

Hence its volume will be 0.902 L at 25.4 KPa

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