Question

A sample of neon occupies a volume of 461 mL at 100 kPa. What will be the volume of the neon when the pressure is reduced to 93.3 kPa? Boyle's law

Answer 1

Given that :

=> P1 = 101.3 kPa

=> P2 = 93.3 kPa

=> V1 = 461 mL

=> V2 = ?

By equation of Boyle's Law

P1V1 = P2V2 .

=>> V2 = P1V1/P2

V2 = 101.3 x 461 /93.3

➡ V2 = 501 ml Neon .

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