Question

A sample of nickel oxide has actual formula ni 0.98 o100. in this sample what fraction of metal ions are ni2+ and ni3+ions

Answer 1

Formula is Ni0.98O1.00
So the ration of Ni : O = 98:100
So if there are 100 atoms of oxygen then 98 atoms of Ni
Let number of atoms of Ni+2 = x
Then number of atoms of Ni+3 = 98–x
Charge on Ni = charge on O
So that oxygen has charge –2
3(98–x) + 2x = 2 (100)
294 –3x +2x = 200
–x = – 94
x = 94
Percentage of Ni+2 = (atom of Ni+2/total number of atoms of Ni)100
=100(94/98)*100
= 96%
Percentage of Ni+3
=100 – Ni+2
=100 – 96
= 4 %
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