Question

A sample of nitrogen gas was taken through the
cyclic process shown in the figure. The ratio of
energy released by the gas in the isochoric process
to change in internal energy in the isobaric process
is
1) 2
2) 0.5
3) 1.5
4)1​

Answer 1

Answer:

Ratio of heat released in the isochoric process with the change in internal energy of isobaric process is 1 : 1

Explanation:

In isobaric process we know that

$PV = nRT$

now we have

$V = \frac{nR}{P} T$

here we know that the pressure is constant so graph between V and T is a straight line

So here the isobaric process is the one which is represented by straight line passing through origin

SO here in isobaric process change in internal energy is given as

$\Delta U = nC_v\Delta T$

now when we find the energy released in isochoric process then we have

$Q = W + \Delta U$

here in isochoric process we know that work done by the gas is zero

so we have

$Q = \Delta U = nC_v \Delta T$

Since change in temperature is same in both parts as per graph

so the ratio of the two is given as

$Q : \Delta U = 1 : 1$

#Learn

Topic : Thermodynamics

https://brainly.in/question/78895