Question

a sample of oxygen gas weighting 8.5g at a pressure of 90.0cm of mercury occupies a volume of 10.5 litre when it temperature is 270 kelvin what is volume when the temperature is raised to 360 kelvin at a same pressure​

Answer 1

Answer :-

→ $\boxed{\rm\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}}$

→ $\rm\frac{1.18 \times 10.75}{270} = \frac{1.18 \times V_2}{360}$

→ 3.28 × 10⁻³ V₂ = 0.046

→ V₂ = 0.046/3.28 × 10⁻³

→ V₂ = 14.02 L

Hence the gas would occupy a volume of 14.02 L

Answer 2

$\huge\mathfrak\red{Answer}$

$\sf \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\\ \frac{1.18\times 10.5}{270} = \frac{1.18 \times V_2}{360} \\\\\frac{12.39}{270} = 3.28 \times 10^{-3} V_2 \\\\ V_2 = \frac{0.046}{3.28\times 10^{-3}} \\\\V_2 = 14.02$

Volume = 14.02 L