Question

a sample of oxygen gas weighting 8.5g at a pressure of 90.0cm of mercury occupies a volume of 10.5 litre when it temperature is 270 kelvin what is volume when the temperature is raised to 360 kelvin at a same pressure​

Answer 1

Answer :-

$\rm\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$

$\rm\frac{1.18 \times 10.75}{270} = \frac{1.18 \times V_2}{360}$

3.28 × 10⁻³ V₂ = 0.046

V₂ = 0.046/3.28 × 10⁻³

V₂ = 14.02 L

Hence the gas would occupy a volume of 14.02 L

Answer 2

$</p><p></p><p>\boxed{\rm\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}}</p><p>$

$2701.18×10.75=3601.18×V2</p><p></p><p>$

3.28 × 10⁻³ V₂ = 0.046

V₂ = 0.046/3.28 × 10⁻³

V₂ = 14.02 L

Hence the gas would occupy a volume of 14.02 L