Question

a sample of oxygen gas weighting 8.5g at a pressure of 90.0cm of mercury occupies a volume of 10.5 litre when it temperature is 270 kelvin what is volume when the temperature is raised to 360 kelvin at a same pressure ​

Answer 1

$\sf \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\\ \frac{1.18\times 10.5}{270} = \frac{1.18 \times V_2}{360} \\\\\frac{12.39}{270} = 3.28 \times 10^{-3} V_2 \\\\ V_2 = \frac{0.046}{3.28\times 10^{-3}} \\\\V_2 = 14.02$

Volume = 14.02 L