Question

A sample of ozone contained 1.08 * 1020 atoms of O. Find moles of O, in mixture ?
(Use N = 6 * 1023)
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Answer 1

Answer:

0.18×10^-3

Explanation:

moles ×NA =1.08×10^20

moles of oxygen =1.08×10^20/6×10^23

=0.18×10^-3

Answer 2

Given:

Atomic weight of ozone(O₃)=(8+8)×3=48 amu

Number of O atoms=1.08×10²⁰atoms

Number of particles(N)=6×10²³

Number of moles of O₃ in mixture=?

To find moles of O₃  in the mixture

Solution:

$Number of particles=Number of O_{3} atoms/Number of moles of O_{3} in the mixture$

⇒6×10²³ = 1.08×10²⁰/Number of moles of O₃ in mixture

Number of moles=0.00018 mole

Hence, 0.00018 moles of O₃ are present in the mixture.

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