Question

A sample of pure calcium carbonate was found
to contain 40% calcium, 12% carbon and 48% oxygen.
Assuming the truth of law of constant composition, find out
weight of calcium, carbon and oxygen in 5.00 g of another
sample of calcium carbonate.
(Ans. Ca = 2.0g. C =0.6g: 0 = 2.4 g)​

Answer 1

Explanation:  Since, mass percentage of Ca in CaCO  

3

​

=40% and law of constant proportion is true.

So, the mass percentage of Ca in 5gm CaCO  

3

​

 will also be 40%.

Hence,40% of 5gm =5×  

100

40

​

 =2gm

Answer 2

Answer:

Calcium = 40% ; Carbon = 12% ; Oxygen = 48%

Total weight = 5.00 g

Weight of calcium = 40*5/ = 2.00 g

Weight of Carbon = 12*5/ = 0.6 g

Weight of Oxygen = 48*5/ = 2.4 g

Explanation:

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