Chemistry, asked by sanchali30, 4 months ago

A sample of pure compound contains 1.15 g of sodium, 3.01 × 1022 atoms of carbon and 0.1 mol
of oxygen atom. Its empirical formula is

Answers

Answered by Anonymous
5

Answer:

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I hope it is helpful for you

Answered by rsagnik437
11

Answer:-

Empirical formula of the compound

is NaCO .

Explanation:-

• Molar mass of sodium = 23g/mol

• Avogadro Number = 6.022×10²³

Let us calculate the molar ratio of each type of atoms.

Number of moles in 1.15g of Sodium (Na):-

= Given Mass / Molar mass

= 1.15/23

= 0.05 mole

Number of moles in 3.01×10²² atoms of

Carbon (C) :-

= No of atoms / Avogadro Number

= 3.01×10²²/6.022×10²³

= 0.5/10

= 0.05 mole

Number of moles of Calcium atom = 0.1

The atomic ratio of Na : C : O is :-

= 0.05 : 0.05 : 0.1

• Least value = 0.05

Now, we will divide each value by the least value.

=> [0.05/0.05] : [0.05/0.05] : [0.1/0.05]

=> 1 : 1 : 2

Thus, the empirical formula is NaCO .

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