Question

A sample of sodiumcarbonate weighing 0.53gram is added to 101cc of 0.1N sulphuric acid will the resulting solution be the acidic & basic or neutral?​

Answer 1

$\sf\fbox\red{Given:-}$

• weight of sodium carbonate (W) = 0.62g
• The equivalent wt. of sodium carbonate (E) = 62g

$\sf\fbox\red{Find:-}$

• Will the resulting solution be the acidic & basic or neutral?

$\sf\fbox\red{Solution:-}$

On adding sodium carbonate to sulphuric acid, following reaction takes place:

$\sf \rightarrow Na₂CO₃ + H₂SO₄ ---→ NA₂SO₄ + CO₂ + 2H₂O</p><p></p><p></p><p>$

Now,

we will determine normality of sodium carbonate.

$\sf\small\red{Formula}$

$\sf \: W = \frac{N \times E \times V}{1000}$

$\sf\small\red{Final \: answer:-}$

$\sf \: N = \frac{0.62 \times 1000}{62 \times 1000}$

$\sf\small\red{Note:-}$

Since normality of both the solutions is same.

Hence resulting solution will be neutral.

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