Question

A sample of soil was placed in a water content tin of mass 19.52 g. the combined mass of the soil and the tin was 48.27 g. after oven drying 9for 24 h at 110 oc) the soil and the tin had a mass of 42.31 g. determine the water content of the soil.

Answer 1

Mass of the tin = 19.52g

Mass of tin + soil + content = 48.27 g

Mass of soil + content = 48.27 - 19.52 = 28.75

After heating:

Mass of soil + tin = 42.31

Mass of soil = 42.31 - 19.52 = 22.79

Mass of content = mass of soil + content - mass of soil

= 28.75 - 22.79 = 5.96 g

Mass of content = 5.96

Answer 2

Answer:

26.15 %

Explanation:

Mass of the tin = 19.52g

Mass of tin + soil + water = 48.27 g

Mass of soil + mass of water = 48.27 - 19.52 = 28.75

After heating:

Mass of soil + tin = 42.31

Mass of soil = 42.31 - 19.52 = 22.79

Mass of water = mass of soil + mass of water - mass of soil

= 28.75 - 22.79 = 5.96 g

Mass of water = 5.96

water content = (mass of water/mass of soil) *100

water content = 26.152%