Question

A sample of solution has a mixture of 0.01 M Aluminum Chloride and 0.05 M Magnesium Chloride. What is the molarity of Silver that is required to precipitate all the chloride ions present in the solution? *

Answer 1

Answer:

0.13 moles

Explanation :

In AlCl3; moles of Chlorine = 3 x 0.01 = 0.03 moles

In MgCl2; moles of Chlorine = 2 x 0.05 = 0.1 moles

Total moles of chlorine present in solution = 0.13 moles

Ag + Cl = AgCl

moles of Ag required to precipitate Cl = 0.13