Math, asked by jhumibk7735, 1 year ago

A sample of sucrose is found to contain 72.28 into 10 to the power 21 atoms of carbon find the mass of sample in grams

Answers

Answered by tiwaavi
12
Hello Dear.

Here is the answer---

No. of atoms of Carbon in certain amount of Sucrose = 72.28 × 10²¹ atoms.
Molar Mass of the Carbon = 12 g/mole.
Avogadro's No.(Nₐ) = 6 × 10²³

Now, Using the Formula,

No. of atoms = (Mass/Molar Mass) × Nₐ
72.28 × 10²¹ = (Mass/12) ×  6 × 10²³
⇒72.28 × 2 = Mass × 100
⇒ Mass = 1.44 g.

Now,
Molar Mass of the Sucrose (C₁₂H₂₂O₁₁) = 342 g/mole.
Mass of Carbon Present in 1 mole of Sucrose = 12 × 12
 = 144 g.

Now,
144 g of Carbon is present in 1 mole(342 g) of Sucrose.
∴ 1 g of the Carbon is present in 342/144 g of Sucrose.
∴ 1.44 g of Carbon is present in (342/144) × 1.44 g of Sucrose.
      = 3.42 g of Sucrose. 

∴ Mass of the Sample of Sucrose is 3.42 grams.


Hope it helps.
Answered by abhi178
12
Molecular formula of sucrose = C₁₂H₂₂O₁₁
∵ 1 Molecule of sucrose has 12 atoms of carbon .
∴ 1 mole of sucrose contains 12 mole of Crabon atoms .

First of all we have to find out number of mole of C - atoms
given, number of C - atoms in sucrose sample = 72.28 × 10²¹
so, number of mole of C- atoms in sample = 72.28 × 10²¹/6.023 × 10²³
= 12 × 10⁻² = 0.12 mole

∴ number of mole of sucrose sample = number of mole of C-atoms /12
= 0.12/12 = 0.01 mole
Now, mass of sucrose sample = numbe of mole × molecule mass of sucrose.
= 0.01 × 342 [ ∵ molecular mass of sucrose = 342g/mol ]
= 3.42 g

Hence, mass of sucrose sample is 3.42g
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