a sample of water gas contains 42% by volume of carbon mono oxide if the total pressure is 760mm the partial pressure of carbon mono oxide is
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Explanation:
42% of CO is released
100% − 28g
42% − x
x=
100
42×28
x=11.76
2. for H
2
O
100% − 18g
58% − x
x=
100
58×16
x=10.44
mole of CO =
28
11.76
=0.42
moles of H
2
O =
18
10.44
=0.58
Dalton's law (p) =P
T
×X
Q
=760×
0.42+0.58
0.42
P=319.2mm
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