Chemistry, asked by rohit2112, 8 months ago

A sample of water was analysed and found to contain temporary magnesium
hardness 25 mg/lt. permanent magnesium chloride hardness 15 mg/lt and
permanent calcium sulphate hardness 20 mg/lt., SiO2 = 300 mg/lt. calculate the
lime and soda required for softening 30.000 litre of hard water.????
Lime = 4975.53gm and Soda 969.75gm
Lime = 497.55 gm and Soda 969.75gm
Lime = 49.75 gm and Soda 96.97
no idea​

Answers

Answered by anandkumar304
3

Explanation:

3 option is the answer bro. Mark that

Answered by krrishdoshi14
0

Answer:

Milligrams per litre (mg/l): The number of milligrams of calcium carbonate equivalent hardness presents in litre of water. 1 mg/L = 1 mg of CaCO3 eq hardness in 1 litre of water. But one litre of water weights =1 kg =1000g = 1000 x 1000 mg = 106 mg = 1 ppm. 3.

Similar questions