Math, asked by changkyun, 1 year ago

A sample proportion of 0.62 is found. To determine the margin of error for this statistic, a simulation of 200 trials is run, each with a sample size of 100 and a point estimate of 0.62.

The minimum sample proportion from the simulation is 0.73, and the maximum sample proportion from the simulation is 0.97.


What is the margin of error of the population proportion using an estimate of the standard deviation?

A) 0.02
B) 0.08
C) 0.12
D) 0.16

Answers

Answered by silu12
12
0.08
.....................
Answered by bandameedipravalika0
0

Answer:

Concept :

The standard deviation is a statistic that expresses how much variance or dispersion there is in a group of numbers. While a high standard deviation suggests that the values are dispersed throughout a larger range, a low standard deviation suggests that the values tend to be near to the established mean. Lowercase SD is typically used to represent it in mathematical writings and formulae. A random variable, sample, statistical population, data set, or probability distribution's standard deviation is equal to the square root of its variance. Although less resilient in practise, it is algebraically easier than the average absolute deviation. The fact that the standard deviation is expressed in the same unit as the data, as opposed to the variance, makes it a valuable statistic.

Step-by-step explanation:

Since the range of sample proportions is 0.97-0.73 = 0.24

Find the standard deviation :

Range = 6*(s-bar)

          = 0.24

s-bar = 0.04

Then s/sqrt (100) = 0.04

and s = 0.4

S.D = 0.04 + 0.04

      = 0.08

#SPJ2

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