Question

A sample space consists of 3 samples with associated probabilities given as 2p, p2, 4p – 1,then the value of p is

Answer 1

for sample space
the sum of probability is 1
$p^2+2p+4p-1=1$
$p^2+6p-2=0$
$p= \frac{-6+ \sqrt{36+8} }{2}= \frac{-6+ \sqrt{44} }{2}= \sqrt{11}-3$
so the value of p is 0.3166

Answer 2

sum of all probabilities is 1
so u get p^2=6p-2=0
solve it and u get
p=(11)^0.5-3