Math, asked by kota029342, 2 months ago

a) Sanya,Aarushi,Manav and Kabir made greeting card. Complete the table for their cards:
Whose card Length width perimeter area
Sanya. 10cm. 8cm
Manav. 11cm. 44cm
Aarush. 8cm. 80 square cm
Kabir. 40cm 100 square cm​

Answers

Answered by ashising2006
21

Answer:

whose card Length width perimeter Areas

sanya 10 cm 8 cm 36 cm 80 sq.cm

Manav 11 cm 11 cm 44 cm 121 sq.cm

Aarushi 10 cm 8 cm 36 cm 80 sq.cm

Kabir 10 cm 10 cm 40 cm 100 sq.cm

sanya

we have length = 10 cm and width = 8 cm

perimeter =2(2+b)

= 2(10+8) = 2(18)

= 36 cm

Length of Manav's card =11 cm

Perimeter of his card =44 cm

Perimeter of card = sum of all its sides

=11+11+sum of other 2 sides

= 22+sum of other 2 sides

Now, sum of other two sides, 44-22=22 cm

so, width of manav's card =22/2, 11 cm

width of Arushi's card = 8 cm Area of card

=8×10=80cm

2

Now, we have to find length

Area of the card =80 cm

Length of Arushi's card = 80/8=10 cm.

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