Question

a) सरल रेखा 3x +9y = 3 का ढाल एवं अन्तः खण्ड का मान
ज्ञात करो।
2
Find the slope and intercept of straight line
-3r+9y = 3.​

Answer 1

$\underline{\textbf{Given:}}$

$\textsf{Line is}$

$\mathsf{-3x+9y=3}$

$\underline{\textbf{To find:}}$

$\textsf{Slope intercept of the straight line}$

$\underline{\textbf{Solution:}}$

$\underline{\textbf{Slope intercept form:}}$

$\boxed{\mathsf{y=mx+c}}$

$\mathsf{Consider,}$

$\mathsf{-3x+9y=3}$

$\textsf{This can be written as}$

$\mathsf{9y=3x+3}$

$\mathsf{y=\dfrac{3}{9}x+\dfrac{3}{9}}$

$\mathsf{y=\dfrac{1}{3}x+\dfrac{1}{3}}$

$\textsf{Comparing with y=mx+c, we get}$

$\mathsf{m=\dfrac{1}{3}\;\;\&\;\;c=\dfrac{1}{3}}$

$\therefore\mathsf{Slope=\dfrac{1}{3}\;\&\;y-intercept=\dfrac{1}{3}}$

$\underline{\textbf{Find more:}}$