A satelite is revolving very close to earth.What is percantage increase in velocity need to make it escape from the gravitational field of the earth?
Answers
Answered by
0
Answer:
multiply orbital velocity of satellite with underoot of 2
Explanation:
by multiplying orbital velocity of satellite with underoot of 2 gives the escape velocity from that orbit
Answered by
0
Answer:
Escape velocity, ve=
2
⋅v
0
=1414v
0
Fractional increase In orbital velocity
v
Δv
=
v
0
v
e
−v
0
=0.414
∴ Percentage increase =41.4%
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