Question

A satellite A of mass m is at a distance of r from the surface of the earth Another satellite B of mass 2m is at distance of 2r from the earth centre their time periods are in ratio of

Answer 1

Time period is not dependent on mass of satellite.

Time period(T) = 2π√r³/√GM ( M is mass of earth)

T² is directly proportional to r³

Therefore,

Ratio = r³/(2r)³

= r³/8r³

= 1:8

Answer 2

According to Kepler's law T2 ∝R3 note periodic time is independent of mass

Taking the ratio of periodic time we get