Math, asked by itsmerjun, 1 month ago

A Satellite flying at height h is watching the top of the two tallest mountains in Uttarakhand and Karnataka,them being Nanda Devi(height 7,816m) and Mullayanagiri (height1,930m). The angles of depression from the satellite,to the top of Nanda Devi and Mullayanagiri are cot−1 (√3) and tan−1 (√3) respectively. If the distance between the peaks of the two mountains is 1937km,and the satellite is vertically above the midpoint of the distance between the two mountains.
1. The distance of the satellite from the top of Nanda Devi is
a) 1139.4 km b) 577.52 km c) 1937 km d) 1025.36 km

2. The distance of the satellite from the top of Mullayanagiri is
a) 1139.4 km b) 577.52 km c) 1937 km d) 1025.36 km

3. The distance of the satellite from the ground is
a) 1139.4 km b) 577.52 km c) 1937 km d) 1025.36 km

4. What is the angle of elevation if a man is standing at a distance of 7816m from Nanda Devi?
a) sec^-1 (2) b)cot^-1 (1) c)sin^-1 (√3/2) d) cos^-1 (1/2)

5. If a mile stone very far away from, makes cos^-1 (1/√2) to the top of Mullanyangiri mountain. So,find the distance of this mile stone from the mountain.
a) 1118.327 km b) 566.976 km c) 1937 km d) 1025.36 km​

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Answers

Answered by maswanthmjagatheeshw
2

Step-by-step explanation:

  1. a) 1139.4 km.
  2. c) 1937 km.
  3. b) 577.52 km
  4. 45°
  5. c) 1937 km
Answered by naziahassan7547
0

Answer:

the distance of the satellite from the ground is

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