Question

A satellite having mass 1/4 of earths mass . What time it will take to complete one revolution above the earths surface at a height 35780 km?

Answer 1

Time to complete revolution by satellite is 12 hrs

Explanation:

Use the formula  T = 2π √R^3 / GM(e)

Here, T is time period, R is orbit radius

G is gravitational constant and M(e) is mass of earth.

Given data:

= 4 × original mass of earth = 4 × 5.92 × 10²⁴ kg

Orbit radius , R = Earth's radius + height of satellite from Earth's surface

= 6400 km + 35780 km

= 42180 km = 4.2180 × 10⁷ m

G = 6.67 × 10⁻¹¹ N.m²/Kg²

Now, T = 2π√{(4.2180 × 10⁷)³/(6.67 × 10⁻¹¹) × (4 × 5.92 × 10²⁴)}

= 43309.8 sec

So, T = 43309.8/3600 ≈ 12 hrs

Hence, time to complete revolution by satellite is 12 hrs

Also learn more

A satellite is moving around the earth with speed v in a circular orbit of radius r .if the orbit radius is decreased by 1% its speed will?

https://brainly.in/question/3600528