Question

A satellite having mass 1/4 of the earth's mass. What will be the time it will takecomplete on (revolution) orbit above the earth's surface at a height of 35780 km?

Please solve this !!!​

Answer 1

Answer:

Question is Length y

Time = 2πR/V

R = given

V = orbital velocity = √2GM/r

r = R + 6400KM

distance from Center of Earth

M = M/4

Earth mass not given in question

or

Fcp = MV^2/R

R = distance between satellite & Earth

Fcp = FG = GMM'/R

M' = M/4

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