A satellite is in an orbit with a perigee of 1000 km and an apogee of 4000 km. Using a mean earth radius of 6378.14 km, find the period of the orbit in hours, minutes, and seconds
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Given A satellite is in an orbit with a perigee of 1000 km and an apogee of 4000 km. Using a mean earth radius of 6378.14 km, find the period of the orbit in hours, minutes, and seconds
Apogee height = h a
Perigee height = h p
r a = h a + R
= 4000 + 6378.14
= 10378. 14 km
r p = h p + R
= 1000 + 6378.14
= 7378.14 km
We get a = r a + r p
a = 17,756.28
Now T = √4π^2 a^3 / G M
G = 6.672 x 10^-11 m^3/kg/s^2
M = 5974 x 1024 kg
So T = 8320.95 secs
T = 2 hrs 19 min 8 secs
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