Question

A satellite is moving with a constant speed ‘V’ in a circular orbit about the earth. An object of mass ‘m’ is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of its ejection, the kinetic energy. Of the object is
(a) ½ mV2
(b) mV2
(c) 3/2 mV2
(d) 2mV2

Answer 1

Answer:

(a)1/2 mv2

Explanation:

because the circular path of the satellite is V and ejected point is m and it should be multiplied with each other and with 2 and should divide it with 1/2