Question

.A satellite is projected with a velocity 1.5 times the critical velocity. The path of the satellite will be​

Answer 1

Explanation:

orrect option is

D

3R

According to law of conservation of energy

R

−GMm

+

2

1

mV

2

=

R+h

−GMm

=

R

−GMm

+

2

1

m(

1.5

R

GM

)

2

=

R+h

−GMm

=

R

−GMm

+

4

3

R

GMm

=

R+h

−GMm

⇒h=3R