Question

A satellite is revolving around earth with orbital speed v0. if it stops suddenly then speed with which it strike the surface of earth is (let ve be escape velocity of the earth)

Answer 1

Answer:

Let r be the radius of satellite then,

v○^2=GMrv02=GMr

Applying conservation of Mechanical energy between points A (the satellite position when its suddenly stops ) to point B on the surface of earth where it strikes with velocity v

KEKE=change in potential energy

1212mv2=−GMmr−(−GMmR)mv2=−GMmr−(−GMmR)

v2=2GMR−2GMrv2=2GMR−2GMr

=ve^2−2v○^2

v=(v2e−2v○^2)^1/2

                     Hope it helps u!!!!