Question

A satellite is revolving around the earth in a circular orbit of radius 8000 km.What will be it's period of revolution

Answer 1

hay mate here is your answer

distance = 2πr

=2×22/7×8000

so,there distance covered in one round

=352000/7km

the revolution in one period,

352000km/7

Answer 2

The period of revolution of satellite around the earth is 7121 s.

Explanation:

The time period of the satellite revolving around Earth is given as

$T=2\pi\sqrt{\frac{r^3}{GM} }$

Here, r is the radius of the orbit G is the gravitational constant and M is the mass of the Earth.

Given r = 8000 km and we know $G=6.67\times10^-^1^1m^3kg^-^1s^-^2$ and $M =5.97\times10^2^4kg$.

Substitute the values, we get

$T=2\times3.14\sqrt{\frac{(8000000m)^3}{6.67\times10^-^1^1\times5.97\times10^2^4} }$

T = 7121 s

Thus, the period of revolution of satellite around the earth is 7121 s.

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