A satellite is revolving in a circular orbit of radius R.Ratio of KE and its PE is (only magnitude)
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Given: A satellite is revolving in a circular orbit of radius R
To find: Ratio of KE and its PE?
Solution:
- Now we have given the radius as R.
- We know that kinetic energy of a satellite revolving at a height 'h' from Earth's surface is given by:
KE = GMm / 2(R + h)
- And the potential energy is given by:
PE = - GMm / (R + h)
- So the ratio becomes:
KE / PE = GMm / 2(R + h) / - GMm / (R + h)
KE / PE = -1/2
Answer:
So the ratio of KE and its PE is -1/2.
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