Science, asked by ayan98542, 1 year ago

A satellite is revolving in a orbit at an altitude 330 km from the surface of the earth . calculate it's orbital velocity and tune period .
Given that R = 6370km
M = 5.98 x 10^24 kg
G = 6.67 x 10^-11 Nm²/kg²​

Answers

Answered by Anonymous
0

Answer:

Explanation:

Distance of the Moon from the Earth = 3.84 × 105 km, F ... Here, G = 6.67 × 10–11 N m2/kg2, M1 = 6 × 1024 kg; M2 = 7.4 × 1022 kg. R ... provided by the gravitational force between the two.

Answered by nihasrajgone2005
0

Answer:

Given that R = 6370km

M = 5.98 x 10^24 kg

G = 6.67 x 10^-11 Nm²/kg²

hope this helps ❤️

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