Question

A satellite is revolving round the earth with orbital speed v0. If it stops suddenly, the speed with which it will strike the surface of earth would be- (ve = escape velocity of a particle on earth's surface)

Answer 1

Let r be the radius of satellite then,

v○^2=GMrv02=GMr

Applying conservation of Mechanical energy between points A (the satellite position when its suddenly stops ) to point B on the surface of earth where it strikes with velocity v

KEKE=change in potential energy

1212mv2=−GMmr−(−GMmR)mv2=−GMmr−(−GMmR)

v2=2GMR−2GMrv2=2GMR−2GMr

=ve^2−2v○^2

v=(v2e−2v○^2)^1/2

Answer 2

Explanation:

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