Physics, asked by vinodmaurya7617, 3 months ago

A satellite of 500 kg is revolving in a circular orbit at a height of 3400 km from the surface of the earth. Calculate the orbital of the satellite and the gravitational force of the earth.

Answers

Answered by adityaAlexHembrom
2

Answer:

मुझे Follow,= तुमहै Follow

Explanation:

मुझे Follow,= तुमहै Follow

Answered by vatsaltshah2495
1

Answer:

here you go

Explanation:

As the satellite is moving in equatorial plane with orbital radius 4×10

7

m.

∴ Satellite is geostationary satellite.

Hence, the time taken by satellite to complete its one revolution, T=24h=86400 s

Velocity of satellite, v= 2πr/t

Angular momentum, L=mvr

L=m(

T

2πr

)r=

T

2πm

r

2

∴L=

86400

2×3.14×500

×(4×10

7

)

2

=0.58×10

14

kg m

2

s

−1

.

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