A satellite of 500 kg is revolving in a circular orbit at a height of 3400 km from the surface of the earth. Calculate the orbital of the satellite and the gravitational force of the earth.
Answers
Answered by
2
Answer:
मुझे Follow,= तुमहै Follow
Explanation:
मुझे Follow,= तुमहै Follow
Answered by
1
Answer:
here you go
Explanation:
As the satellite is moving in equatorial plane with orbital radius 4×10
7
m.
∴ Satellite is geostationary satellite.
Hence, the time taken by satellite to complete its one revolution, T=24h=86400 s
Velocity of satellite, v= 2πr/t
Angular momentum, L=mvr
L=m(
T
2πr
)r=
T
2πm
r
2
∴L=
86400
2×3.14×500
×(4×10
7
)
2
=0.58×10
14
kg m
2
s
−1
.
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