A satellite of earth revolves in a circular orbit of height of 300 km above the earth's surface.
Calculate:
Orbital velocity
Period of revolution of satellite
Given : R= 6.4*10^6m and g= 10m/s sq
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The orbital velocity of the satellite is v=
R+h
GMG
where M= mass of earth and R= radius of earth.
so, v=
(6.4×10
6
)+(0.25×10
6
)
6.67×10
−11
×(6×10
24
)
=7.76 km/s
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