a satellite of mass 100kg perform uniform circular motion around earth at height 6400km from earth surface. Find its gravitational potential energy
Answers
640000
Explanation:
multiply 100 into 6400
Gravitational Potential energy of the satellite is 6272000 joules.
Explanation:
Given data
Mass of the satellite = 100 Kg
Height at which the satellite is located from the earth = 6400 km
Find the Gravitational Potential energy of the satellite
- The potential energy of an object present in a gravitational field is called as Gravitational Potential Energy.
- This find application in satellites revolving around the earth surface.
- For the satellites, the lift force is based on its weight and they are equal also.
- Hence, the Gravitational Potential Energy is equal to the product of the weight of the satellite and the height at which it revolves.
Gravitational Potential energy = Weight × height
Weight = mass (m) × gravity (g)
Gravitational Potential energy = mass (m) × gravity (g) × height (Joules)
Gravitational Potential energy = m × g × h (Joules)
Substitute the respective values in above equation, where g = 9.8 (m/s²)
Gravitational Potential energy = 100 × 9.8 × 6400 (Joules)
Gravitational Potential energy = 6272000 (Joules)
Therefore the Gravitational Potential energy of the satellite is 6272000 Joules.
To Learn More
1)A satellite of 600 kg orbits the Earth at a height of 500 km from its surface. Calculate its (i) kinetic energy (ii) potential energy and(iii) total energy ( M = 6 × 1024 kg ; R = 6.4 × 106 m)
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2)An artificial satellite revolves around the Earth at a distance of 3400 km. Calculate its orbital velocity and period of revolution. Radius of the Earth = 6400 km; g = 9.8 m/s²
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