A satellite of mass m is in orbit round the earth at a distance of 2.5 r above its surface. If the gravitational field strength at the earth's surface is g. Calculate the centripetal force acting on the satellite
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Answer:
mv^2/3.5R.
Explanation:
We get that the satellite with mass m is rotating around the earth in a orbit with the acceleration of a and also having a centripetal force.
Acceleration is a=v^2/R where R is the radius of the earth. Since, the orbit is at a height h then the acceleration is a=v^2/(R+h).
So, the centripetal force will be F=ma. Since the height h=2.5R given. So, the force will be F=m*v^2/(R+2.5R). Which on solving we will get that mv^2/3.5R. Which will be the centripetal force of the body acting on the satellite.
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