Question

A satellite of mass m is orbiting the earth at a height h from its surface the total energy of the satellite in term of go the value of g at earth surface zigyasa

Answer 1

Answer:

The answer is E = - g0 ms x R^2 / 2(R+h)

Explanation:

Gravitational potential energy at height 'h' is

Uh = -GMm / R+h

Uh=-gR^2m / R+h

Where "Uh" represents Potential energy at height h  and "R" represents Radius of earth

Wherein

Uh = -mgR / 1+ h ÷ R

Thus total energy of satellite is equal to half of its potential energy.

Therefore E= -Gms x Me / 2(R+h)

Since g =GMe / R2 or  GMe = g0R^2}

E = - g0 ms x R^2 / 2(R+h)